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IBPS PO Time and Work Questions with Answers FREE PDF Download IBPS PO is one the primary bank exams of all times. Competitive exam preparation has always been a crucial task involving dedication and commitment.
In this article, we also provide you Important Short Tricks on Time & Work Questions which are asked in bank exams like IBPS. IBPS PO time and work questions with answers FREE PDF download will help you solve maximum number of questions in minimum amount of time. Candidates must take lot of online IBPS PO mock test for practice.
Time and work problems based on this concept are not only a little complicated but also asked very frequently asked in competitive exams. So let’s establish a relation between terms and formulas that help to solve such time and work formulas.
1.
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :  

2.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:  

3.
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?  

4.
5.
10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?  

Time and work is an important topic in IBPS exams, including clerks, PO and specialist officers. In order to make the chapter easy for you all, we provide IBPS PO time and work questions with answers PDF with important short tricks to solve time & work questions will surely make the chapter easy for you all.
6.
X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?  

7.
A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in:  

8.
A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in :  

Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.



10.



ANSWERS
1.
A’s 1 day’s work =  1  ; 
15 
B’s 1 day’s work =  1  ; 
20 
(A + B)’s 1 day’s work =  1  +  1  =  7  .  
15  20  60 
(A + B)’s 4 day’s work =  7  x 4  =  7  .  
60  15 
Therefore, Remaining work =  1 –  7  =  8  .  
15  15 
2.
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 – 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
If difference of time is 60 days, B takes  3  x 60  = 90 days.  
2 
So, A takes 30 days to do the work.
A’s 1 day’s work =  1 
30 
B’s 1 day’s work =  1 
90 
(A + B)’s 1 day’s work =  1  +  1  =  4  =  2  
30  90  90  45 
A and B together can do the work in  45  = 22  1  days. 
2  2 
3.
B’s 10 day’s work =  1  x 10  =  2  .  
15  3 
Remaining work =  1 –  2  =  1  .  
3  3 
Now,  1  work is done by A in 1 day. 
18 
1  work is done by A in  18 x  1  = 6 days.  
3  3 
4.
(A + B)’s 20 day’s work =  1  x 20  =  2  .  
30  3 
Remaining work =  1 –  2  =  1  .  
3  3 
Now,  1  work is done by A in 20 days. 
3 
Therefore, the whole work will be done by A in (20 x 3) = 60 days
5.
1 woman’s 1 day’s work =  1 
70 
1 child’s 1 day’s work =  1 
140 
(5 women + 10 children)’s day’s work =  5  +  10  =  1  +  1  =  1  
70  140  14  14  7 
5 women and 10 children will complete the work in 7 days.
6.
Work done by X in 4 days =  1  x 4  =  1  .  
20  5 
Remaining work =  1 –  1  =  4  .  
5  5 
(X + Y)’s 1 day’s work =  1  +  1  =  8  =  2  .  
20  12  60  15 
Now,  2  work is done by X and Y in 1 day. 
15 
So,  4  work will be done by X and Y in  15  x  4  = 6 days.  
5  2  5 
Hence, total time taken = (6 + 4) days = 10 days
7.
Formula: If A can do a piece of work in n days, then A’s 1 day’s work =  1  . 
n 
(A + B + C)’s 1 day’s work =  1  +  1  +  1  =  7  .  
24  6  12  24 
Formula: If A’s 1 day’s work =  1  ,  then A can finish the work in n days. 
n 
So, all the three together will complete the job in  24  days  =  3  3  days.  
7  7 
8.
(A + B)’s 1 day’s work =  1  +  1  =  1  .  
15  10  6 
Work done by A and B in 2 days =  1  x 2  =  1  .  
6  3 
Remaining work =  1 –  1  =  2  .  
3  3 
Now,  1  work is done by A in 1 day. 
15 
2  work will be done by a in  15 x  2  = 10 days.  
3  3 
Hence, the total time taken = (10 + 2) = 12 days.
9.
I. (10 x 6) men can complete the work in 1 day.
1 man’s 1 day’s work =  1 
60 
II.  10 x  24  men +  10 x  24  women can complete the work in 1 day.  
7  7 
240  men’s 1 day work +  240  women’s 1 day work = 1.  
7  7 
240  x  1  +  240  women’s 1 day’s work = 1.  
7  60  7 
240  women’s 1 day’s work =  1 –  4  =  3  
7  7  7 
10 women’s 1 day’s work =  3  x  7  x 10  =  1  
7  240  8 
So, 10 women can finish the work in 8 days.
III. (10 men’s work for 3 days) + (10 women’s work for 4 days) = 1
(10 x 3) men’s 1 day’s work + (10 x 4) women’s 1 day’s work = 1
30 men’s 1 day’s work + 40 women’s 1 day’s work = 1
Thus, I and III will give us the answer.
And, II and III will give us the answer.
Correct answer is (A).
10.
I.  20  work can be completed by (8 x 8) workers in 1 day. 
100 
Whole work can be completed by (8 x 8 x 5) workers in 1 day.
=  8 x 8 x 5  workers in 10 days = 32 workers in 10 days. 
10 
II. (20 x 16) workers can finish it in 1 day.
(20 x 16)  workers can finish it in 10 days.  
10 
32 workers can finish it in 10 days.
III.  1  work can be completed by (8 x 5) workers in 1 day. 
8 
Whole work can be completed by (8 x 5 x 8) workers in 1 day.
=  8 x 5 x 8  workers in 10 days = 32 workers in 10 days. 
10 
Any one of the three gives the answer.
Correct answer is (E).
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