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Hello Aspirants. Welcome to Online Quantitative Aptitude Section in Examin.co.in. Here we are creating question sample in Number Series, which is common for all the competitive exams. This quiz contains important questions which match the pattern of banking exams, so make sure you attempt today’s Quantitative Aptitude IBPS Clerk Quiz to check your preparation level. Most important questions of Number Series. We have included Some questions that are repeatedly asked in bank exams !!!
1.
How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?  

2.
3.
Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:  

4.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:  

5.
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?  

Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
6.



7.



8.



Solutions
1.
Speed of the train relative to man  = (63 – 3) km/hr  
= 60 km/hr  




Time taken to pass the man 


= 30 sec. 
2.
Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x =  (120 + 120) 
12 
2x = 20
x = 10.
Speed of each train = 10 m/sec =  10 x  18  km/hr = 36 km/hr.  
5 
3.
Relative speed = (60 + 40) km/hr =  100 x  5  m/sec  =  250  m/sec.  
18  9 
Distance covered in crossing each other = (140 + 160) m = 300 m.
Required time =  300 x  9  sec  =  54  sec = 10.8 sec.  
250  5 
4.
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 – 36) km/hr
=  10 x  5  m/sec  
18 
=  25  m/sec  
9 
2x  =  25  
36  9 
2x = 100
x = 50
5.
Speed of train relative to jogger = (45 – 9) km/hr = 36 km/hr.
=  36 x  5  m/sec  
18 
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m.
Time taken =  360  sec  = 36 sec.  
10 
6.
Time taken to cross the train, running in opposite directions 
=  (l_{1} + l_{2})  sec. 
(u + v) 
10 =  (210 + 300) 
(u + v) 
u + v = 51.
Time taken to cross the train, running in same direction =  (l_{1} + l_{2})  sec. 
(u – v) 
30 =  (210 + 300) 
(u – 60 x (5/18)) 
u =  17 +  50  m/sec.  
3 
Thus, u and v can be obtained.
Correct answer is (E)
7.
Let the two trains of length a metres and b metres be moving in opposite directions at u m/s and v m/s.
Time taken to cross each other =  (a + b)  sec. 
(u + v) 
Now, b = 180, u + v =  150 x  5  m/sec  =  125  m/sec.  
18  3 
9 =  a + 180 
(125/3) 
a = (375 – 180) = 195 m
8.
Time taken by train to cross a man =  Length of train  Speed =  l  ….(i) 
Speed of train  9 
Time taken by train to cross a platform = 
(Length of train + Length of platform) 
Speed =  l + 240  ….(ii) 
Speed of train  24 
From (i) and (ii), we get  l  =  l + 240  . 
9  24 
Thus, l can be obtained. So both I and II are necessary to get the answer.
The correct answer is (E)
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